Question

there are two numbers such that the sum of the numbers is 48 and their difference is 8 find the difference of their squares ​

Answer 1

x+y=48

x-y=8 -> x=y+8

x+y=48

-> y+8+y=48

-> 2y = 40

y=20,

x=28

Hope it helps you :)

Answer 2

Answer:

Below

Explanation:

x+y=48

x-y=8 -> x=y+8

x+y=48 -> y+8+y=48 -> 2y = 40 -> y=20, x=28