Question

There are two numbers such that the sum of twice
the first number and thrice the second number is
100 and the sum of thrice the first number and
twice the second number is 120. Which is the
larger number?​

Answer 1

Answer:

32

Step-by-step explanation:

1). 2X + 3Y = 100 multiply by 2, 4X + 6Y = 200

2). 3X + 2Y = 120 multiply by 3, 9X + 6Y = 360 Subtract eqn 1. from eqn 2. to eliminate 6Y

3). We get 5X = 160, X = 32, 64 + 3Y = 100, 3Y = 100–64 = 36, Y = 12

4). So X is the larger one = 32

Hope it helps you ....

Answer 2

Step-by-step explanation:

Acd. to question -

2x + 3y = 100........(i)

3x + 2y = 120.....(ii)

Multiplying (i) by 3 and (ii) by 2 then subtracting (i) from (ii)

6x + 9y = 300

6x + 4y = 240

5y = 140

y = 28

x = 8

Hope it helps

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