Question

there are two numbers such that their product is 28 and the sum of their squares is 65 find square of sum of the number

Answer 1

$let \: two \: numbers \: be \: a \: \: b \\ given \: a \times b = 28 \\ {a }^{2} + {b}^{2} = 65 \\ {(a + b)}^{2} = 65 + 2 \times 28 \\ = 121 \\ so \: a + b = 11$
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