there are two numbers that have the sum of 19 and the difference of 3 what are the two numbers
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Answer:
let 1st no. be x
and 2nd no. be y
then,
x+y= 19______1
x-y= 3_______2
from equation 2nd we have
x= 3+y_______3
now substitute value of x in equation 1
then we have,
3+y+y=19
3+2y= 19
2y=19-3
y=16/2
y=8
now substitute value of y in equation 3
then we have,
x=3+8
x=11
Step-by-step explanation:
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