Question

There are two numbers. The ratio of their sum, their
difference and their product is 7:3:8. Find the
smaller of the two numbers.
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Answer 1

Answer:

let's find their ratio = 7:3:8 = 7+3+8

= 18

the 1st ratio = 7/18 × 2 (there are 2 numbers) = 0.7bar

the 2nd ratio = 3/18 × 2 = 0.3bar

the 3rd ratio = 8/18 × 2 = 0.8bar

so the smaller of two numbers is 0.3bar

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