there are two numbers. the sum of 4 times the first number and 3 times the second number is 24 the diffences between 2 times the first number and 3 times the second number is 12 find the two number
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Let the no. be X and y
a/q
4x +3y=24
x=24-3y÷4......1
and
2x-3y =12.......2
By substitution method
substituting the value of X from eqn 1 to 2 we get
2(24-3y/4)-3y=12
48-6y/4 -3y=12
48-6y-12y/4=12
48-18y=12×4
48-18y=48
-18y=48-48
y=0/18
putting the value of y in eqn 1 find x.
hope it helps you mate please mark as brainliest.
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