Question

There are two numbers. When 50% of the first number is added to the second number, the resultant number is 3 times th first number.What is the ratio of 1st number to
the 2nd number?
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Answer 1

Answer:

C:23

Step-by-step explanation:

your answer above the photo

Answer 2

Answer:

The ratio of the $1^{st}$ number to the $2^{nd}$ number is $2:5$.

Step-by-step explanation:

Let the first number be $x$.

And the second number be $y$.

According to the question,

50% of the first no. is added to the second number then resultant number is $3$ times the first number, i.e.,

⇒ $50$% of $x+y=3x$

⇒ $\frac{50}{100}\times x+y=3x$

Simplify as follows:

⇒ $\frac{x}{2}+y=3x$

Subtract $3x$ from both the sides.

⇒ $\frac{x}{2}-3x+y=3x-3x$

⇒ $\frac{x-6x}{2}+y=0$

⇒ $-\frac{5x}{2}+y=0$

Now, subtract $y$ from both the sides.

⇒ $-\frac{5x}{2}+y-y=0-y$

On simplifying, we get

⇒ $-\frac{5x}{2}=-y$

⇒ $\frac{5x}{2}=y$

Divide the equation by $y$, we get

⇒ $\frac{5x}{2y}=1$

Lastly, multiply the equation by $\frac{2}{5}$ as follows:

⇒ $\frac{2}{5}\times \frac{5x}{2y}=\frac{2}{5}\times1$

⇒ $\frac{x}{y}=\frac{2}{5}$

Observe that $\frac{x}{y}$ is written as the ratio of $1^{st}$ number to the $2^{nd}$ number.

Therefore, the ratio of the $1^{st}$ number to the $2^{nd}$ number is $2:5$.

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