Question

There are two numbers, when first number is increased by 160%, the obtained number is 86 less than second number and if the first number is increased by 110 then the obtained number is 200 less than the second number. Find out the sum of two numbers?​

Answer 1

The sum of two number is 906.8.

Step-by-step explanation:

Since we have given that

Let the first number be 'x'.

Let the second number be 'y'.

If the first number is increased by 160%, then the obtained number is 86 less than second number.

$\dfrac{100+160}{100}x=y-86\\\\\dfrac{260}{100}x=y-86\\\\2.6x=y-86\\\\y-2.6y=86$

If the first number is increased by 110 then the obtained number is 200 less than the second number.

$\dfrac{100+110}{100}x=y-200\\\\\dfrac{210}{100}x=y-200\\\\2.1x=y-200\\\\y-2.1x=200$

Using both the equations, we get that

$y=2.6x+86\\\\and\\\\y=2.1x+200\\\\So,\\\\2.6x+86=2.1x+200\\\\2.6x-2.1x=200-86\\\\0.5x=114\\\\x=\dfrac{114}{0.5}\\\\x=228$

Now, put the value of x in first equation:

$y=2.6\times 228+86\\\\y=678.8$

So,the sum of two numbers are

$678.8+228=906.8$

Hence, the sum of two number is 906.8.

# learn more:

Sum of a two digit number and the number obtained by reversing the digits is 110 . If 10 is subtracted from the first number , the new number is 4 more than 5 times the sum of the digits in the first number. Find the first number.

https://brainly.in/question/1008268

Answer 2

Step-by-step explanation:

let the first number is 'x'

and second number is 'y'

x is increased by 160%

x+x*160/100=y-86.............(1)

now x is increased by 110

x +110=y-200

x+310=y.........................(2)

now put the value of y in equation (1)

260*x/100=x+310-86

13x/5-x=224

8x/5=224

x=140

y=450

so sum of two numbers =590