Question

there are two numbers whose sum is 6 and sum of their squares is 20

Answer 1

x+ y= 6
x=6-y

x^2+y^2=20
(6-y)^2+y^2=20
36+y^2-12y+y^2=20
2y^2-12y+36-20=0
2y^2-12y+16=0
y^2-6y+8=0
y^2-2y-4y+8=0
y(y-2) -4(y-2) 0
y-2=0 or y-4=0
y=2 or y=4
when y=2
x=6-2=4
when y=4
x=6-4=2
two no.s are = 4,2
give brainlist

Answer 2

Answer:

The numbers are 4 and 2

Step-by-step explanation:

Let the numbers be x and y.

x+y =6

(x+y)^2=36

x^2+y^2+2xy=36...................(1)

But x^2+y^2=20(given)

So (1) becomes 20+ 2xy =36

2xy=16

xy=8..........................(2)

x+y=6(given)...........(3)

From (2) and (3),

The numbers are 2and 4.

Thank you.