There are two numbers x and y such that sum of two times x and three times y is less than or equal to 360.if the value of x is greater than or equal to 160 then what is the maximum value of y
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A/Q, 2x+3y <=360
2×160+3y <=360
320+3y <=360
3y <=360-320
y <=40
The maximum value of y is 40
2×160+3y <=360
320+3y <=360
3y <=360-320
y <=40
The maximum value of y is 40
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Thanks a lot
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