Question

there are two numbers x and y such that their hcf is 4 and lcm is 48​

Answer 1

Answer:

16;12

Step-by-step explanation:

hcf 12,16=4

lcm12,16=48

Answer 2

The question is incomplete. I have found the answer for the right question. (got the question from other website)

If any change in question, comment. I'll do change the answer.

Answer:

x = 48 , y = 4

Step-by-step explanation:

The product if two numbers = the product of their HCF and LCM .

Thus,

x y = 4 × 48 = 192 ........( 1 )

x ( y+2 ) = 6 × 48 = 288 ......... ( 2 )

( x-2 ) y = 2 × 48 = 96. ........( 3 )

(2) becomes , xy + 2x = 288 ..........( 4 )

( 3 ) becomes , xy - 2y = 96 .........( 5 )

from ( 4 ) 2x = 288 - xy

= 288 - 192 = 96

or x = 48

from ( 1 ) y = 192/x = 192/48

= 4

so x = 48 , y = 4

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