Question

There are two people A and B. The difference between their ages is 16 years. If 6 year ago, the elder one was 3 times as old the younger one, find their present ages:​

Answer 1

Answer:

Elder one:-30

Younger one:-14

Step-by-step explanation:

Solution 1

Let present age of the elder person be:-

( x-6)=3(x-16-6)

x-6=3x-66

2x=60

x=60 /2=30

Solution 2

Let age of the elder and younger persons,  

6 years ago, be  b  and  a  respectively.

b-a=16}

                    a=16/3-1=8

b/a=3}

b=8+16=24

Present age of elder person:-24+6=30

30-16=14

Answer 2

ɢɪᴠᴇɴ:-

★Difference between Their age is = 16 years

★ 6 years ago, the elder one was 3 times as old the younger one.

ᴛᴏ ғɪɴᴅ:-

★ Their present ages

sᴏʟᴜᴛɪᴏɴ:-

✏Case -1 :-

Let the age of the younger person be x.

Then the age of the elder person be y.

✏Case -2 :-

six years ago,

the younger one would be ( x-6) years old & the elder one would be (x+16-6) years old.

✰✰According to the question, we can write _____

x +16 -6 = 3(x-6)

➯ x +10 = 3 x -18

➯ x = 14

Hence, the age of the elder person will be

= ( x+16)

= 14 +16

=30

So, the present age of the younger person & the elder person are 14 years & 30 years respectively.

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