Math, asked by anirudhhjadav123, 11 months ago

There are two pipes P, and P2, through which water flows into a tank at speeds of 2 m/s and 6 m/s respectively. If the cross-sectional areas of the pipes are 15 cm² and 25 cm2 respectively,
and it takes 40 minutes to fill the tank, then find the capacity of the tank (in kilolitres).​

Answers

Answered by bashiralibajard
0

four hundred literd

400 liters

Answered by aditya012
0

Answer:

The capacity of the tank = 43.2 kilolitres

Step-by-step explanation:

Given:

Speed of water flowing through P1 = 2 m/s = 200 cm/s

Speed of water flowing through P2 = 6 m/s = 600 cm/s

Cross-sectional area of P1 = 15 cm^2

Cross sectional are of P2 = 25 cm^2

Time taken to fill the tank = 40 minutes =(40 x 60) seconds

Rate at which P1 fills the tank = 200 x 15

3000 \:   \frac{ {cm}^{3} }{s}

Rate at which P2 fills the tank = 600 x 25

15000 \:  \frac{ {cm}^{3} }{s}

=> Total Volume of water discharged into the tank in 1 second = 3000 + 15000

18000 \:  {cm}^{3}

Now,

Rate x time = capacity of the tank

= 18000 x 40 x 60

43200000 \:  {cm}^{3}

= 43.2 kilolitres

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