Math, asked by deviindra4173, 1 year ago

There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey 4⁄8. Who ate the most of the two pizzas? A. Conor B. Tyler C. Brandon D. Audrey

Answers

Answered by nmalavikamohan
10
Let us assume that each pizza has eight slices. Thus, the total number of slices is 8 x 2 = 16 slices.

Conor ate 1/4 of one pizza, that is
1/4 x 8 = 2 slices
Brandon ate 2/8 of one pizza, that is
2/8 x 8 = 2 slices
Tyler ate 3/4 of one pizza, that is,
3/4 x 8 = 6 slices
Audrey ate 4/8, that is
4/8 x 8 = 4 slices.

Thus, Tyler ate the most of the two pizzas.

Answered by tiwaavi
1
Given conditions ⇒

Corner ate's 1/4 of the Pizza.
Brandon ate's 2/8 or 1/4 of the Pizza.
Tyler ate 3/4 of the Pizza.
Audrey ate's 4/8 or 1/2 of the Pizza.

Now, We need to assume the number of pieces in the Pizza. 
∴ Let the Number of Pieces in one Pizza be 4.
∴ Number of Pieces in 2 pieces = 2 × 4 = 8 Pieces.

Now, 
Corner ate = 1/4 × 8
 = 2 pieces.
Brandon ate = 1/4 × 8 
= 2 pieces.
Tyler ate = 3/4 × 8
 = 3 × 2
 = 6 Pieces.
Audrey ate = 1/2 × 8
 = 4 pieces.

In this we can see that the highest number of the Pieces in both th Pizzas are ate by Tyler, i.e. 6.


Hence, Option B. is correct.


Hope it helps.

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