Physics, asked by SwayamPratham, 6 months ago

There are two point masses of 1 kg each 1 m away from each other. There is no force acting upon them except their mutual gravitation. Using Newton's law of Universal Gravitation(F = G\frac{Mm}{R^{2} }), find how much time the point masses would take to come in contact. You are free to use Calculus. Show your working. Any requests for brainliest are discouraged.

Answers

Answered by lm042901
0

Answer:

While Newton was able to articulate his Law of Universal Gravitation and verify it experimentally, he could only calculate the relative gravitational force in comparison to another force. It wasn’t until Henry Cavendish’s verification of the gravitational constant that the Law of Universal Gravitation received its final algebraic form: F=GMmr2 where F represents the force in Newtons, M and m represent the two masses in kilograms, and r represents the separation in meters. G represents the gravitational constant, which has a value of 6.674⋅ 10− 11 N (m/kg) 2. Because of the magnitude of G, gravitational force is very small unless large masses are involved.

Explanation:

Answered by Aloneboi26
43

Explanation:

Answer:

Answer:While Newton was able to articulate his Law of Universal Gravitation and verify it experimentally, he could only calculate the relative gravitational force in comparison to another force. It wasn’t until Henry Cavendish’s verification of the gravitational constant that the Law of Universal Gravitation received its final algebraic form: F=GMmr2 where F represents the force in Newtons, M and m represent the two masses in kilograms, and r represents the separation in meters. G represents the gravitational constant, which has a value of 6.674⋅ 10− 11 N (m/kg) 2. Because of the magnitude of G, gravitational force is very small unless large masses are involved.

Answer:While Newton was able to articulate his Law of Universal Gravitation and verify it experimentally, he could only calculate the relative gravitational force in comparison to another force. It wasn’t until Henry Cavendish’s verification of the gravitational constant that the Law of Universal Gravitation received its final algebraic form: F=GMmr2 where F represents the force in Newtons, M and m represent the two masses in kilograms, and r represents the separation in meters. G represents the gravitational constant, which has a value of 6.674⋅ 10− 11 N (m/kg) 2. Because of the magnitude of G, gravitational force is very small unless large masses are involved.Explanation:

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