Question

There are two radio nuclei a and

b. a is an alpha emitter and b is a beta emitter. their disintegration constants are in the ratio of 1 : 2. what should be the ratio of number of atom of a and b at any time t so that probabilities of getting alpha and beta particles are same at that instant.

Answer 1

Answer: 2:1

Explanation:

┏─━─━─━─━∞◆∞━─━─━─━─┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗─━─━─━─━∞◆∞━─━─━─━─┛

λA/ λB=1/2

Probability of getting alpha and beta ,particles are same.Thus,rate of disintegration are equal

λANa= λBNB

λA/ λB=Nb/Na=1:2

So answer is 2:1