there are two regular polygons. one is having 3sides more than the other. Difference between their exterior angles is 6
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8th
Maths
Understanding Quadrilaterals
Sum of Measures of Exterior Angles of a Polygon
The difference between the ...
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The difference between the exterior angles of two regular polygons, having the sides equal to (n−1) and (n+1) is 9
∘
. Find the value of n.
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When number of sides of a regular polygon = n−1,
The value of its each exterior angle =
n−1
360
∘
When number of sides of a regular polygon = n+1,
The value of its each exterior angle =
n+1
360
∘
Given,
n−1
360
∘
−
n+1
360
∘
=9
∘
⇒360
∘
(n+1)−360
∘
(n−1)=9
∘
(n+1)(n−1)
⇒360
∘
[n+1−(n−1)]=9
∘
(n+1)(n−1)
⇒360
∘
(2)=9
∘
(n
2
−1)
⇒40
∘
(2)=n
2
−1
⇒80
∘
=n
2
−1
⇒n
2
=81
⇒n=9
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