Math, asked by neethadileep2000, 8 months ago

there are two regular polygons. one is having 3sides more than the other. Difference between their exterior angles is 6​

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Answered by amitkumar9266
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8th

Maths

Understanding Quadrilaterals

Sum of Measures of Exterior Angles of a Polygon

The difference between the ...

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The difference between the exterior angles of two regular polygons, having the sides equal to (n−1) and (n+1) is 9

. Find the value of n.

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When number of sides of a regular polygon = n−1,

The value of its each exterior angle =

n−1

360

When number of sides of a regular polygon = n+1,

The value of its each exterior angle =

n+1

360

Given,

n−1

360

n+1

360

=9

⇒360

(n+1)−360

(n−1)=9

(n+1)(n−1)

⇒360

[n+1−(n−1)]=9

(n+1)(n−1)

⇒360

(2)=9

(n

2

−1)

⇒40

(2)=n

2

−1

⇒80

=n

2

−1

⇒n

2

=81

⇒n=9

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