Question

there are two resistances of 6ohm and 3ohm.calculate the maximum and minimum resistances which you can obtain by combining them ​

Answer 1

GIVEN:

• R1=6Ω
• R2=3Ω

TO FIND:

• Maximum and minimum resistance

SOLUTION:

${\large{\underline{\underline{\mathbb{MAXIMUM}}}}}$

To get the maximum resistance we have to connect the resistors in series.

${ \sf{ R_{(series)}=R_1+R_2}}$

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${ \sf{ R_{(series)}=6 \Omega+3\Omega}}$

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${ \sf{ R_{(series)}=9\Omega}}$

Hence the maximum resistance is 9Ω.

${\large{\underline{\underline{\mathbb{MINIMUM}}}}}$

To get the minimum resistance we have to connect resistors in parallel connection.

$\sf{ \dfrac{1}{R_{(Parallel)}}= \dfrac{1}{R_1}+ \dfrac{1}{R_2}}$

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$\sf{ \dfrac{1}{R_{(Parallel)}}= \dfrac{1}{6}+ \dfrac{1}{3}}$

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$\sf{ \dfrac{1}{R_{(Parallel)}}= \dfrac{1 + 2}{6}}$

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$\sf{ \dfrac{1}{R_{(Parallel)}}= \dfrac{3}{6}}$

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$\sf{ \dfrac{1}{R_{(Parallel)}}= \dfrac{1}{2}}$

$\sf{R_{(Parallel)}=2\Omega}$

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•°•The answers are:-

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➢Maximum=9Ω

➢Minimum=2Ω