Question

there are two roads each of width 8m in the central part of the rectangular lawn of length 110m and breadth 70m. one roads is parallel to the other is parallel to the width of the lawn. what be the cost of spreading sand at the rate of rupees 2.50 per metre square on the road.

Answer 1

FOR RECTANGULAR LAWN.
Length, L = 80m.
Breadth, B= 60m.

For Vertical road:
length= Breadth of rectangle
length = 60m.

Breadth = 10m.

Thus, Area of vertical road
=length × breadth
= 60m ×10m
=600m².

For Horizontal road:
length = length of rectangle.
length = 80m
breadth= 10m.

Thus, area of horizontal road
= length ×breadth
= 800m × 10m
=800m².

Note: The roads overlap in the middle of rectangle and form a square having side of 10m.

FOR SQUARE:
Area of square = Side × Side
Area of square = 10m × 10m
Area of square = 100m².


Therefore,
Area needd of road to be gravel
= Area of vertical road + area of horizontal road - area of square

= 600m² + 800m² -100m²
= 1300m².

If the cost of gravelling for 1m² = Rs 1.20
So, Cost of gravelking for 1300m²
= 1300 ×Rs 1.20
=Rs 1,560. Ans.

Answer 2

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