there are two sections in IX class. the mean of the marks secured by 30 students of section a is 45, that of 50 students of sectiom b is 54. find the mean of all marks of students of the class
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Answer:
Mean of all marks secured by students of both sections is 48.21
Step-by-step explanation:
Mean = (Sum of observations) /(total number of observations)
In section A,
Mean= (Sum of observations) /30=45
→ Sum of observations= 45×30
→ Sum of observations= 1350
In section B,
Mean= (Sum of observations)/50=54
→ Sum of observations= 54×50
→ Sum of observations= 2700
Mean of total marks= (Total sum of observations)/(Total number of observations)= (1350+2700)/(30+54)
= 4050/84
= 48.21
Thus, the mean of all marks secured by students of both sections is 48.21
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