Question

There are two similar cubes. The volume of the smaller is 2,744 in^3 and the volume of the larger is 8,000 in^3. If the surface area of the smaller is 1176in^2. What is the surface area of the larger?

Answer 1

Answer: 2400 in sq

Step-by-step explanation:

Volume of larger cube= $a^{3}$= 8000 in^3

where 'a' represents edge of larger cube.

a=$\sqrt[3]{8000}$

a=20 in

Surface area of larger cube= 6 $a^{2}$

=6*20*20 in sq

=2400 in sq