Question

There are two square s and p . The ratio of there is 4 ratio 25 . If the side of a square s is 6 CM what is the length of the side of p​

Answer 1

Correct Question:

Q: There are two squares S and P. The ratio of their areas is 4 : 25. If the side of the square S is 6 cm, what is the length of side of square P?

Answer:

• The length of side of square P = 15 cm

Step-by-step explanation:

Given that:

• There are two square S and P.
• The ratio of their areas is 4 : 25.
• The side of the square S is 6 cm.
• Let the length of side of square P be x cm.

To Find:

• The length of side of square P.

Formula used:

• Area of a square = (side × side)

Finding the length of side of square P:

• A.T.Q.

⇒ 4/25 = (6 × 6)/(x × x)

⇒ 4(x × x) = 25(6 × 6)

⇒ 4x² = 5² × 6²

⇒ (2x)² = (5 × 6)²

• Power of both sides cancelled.

⇒ 2x = 30

⇒ x = 30/2

⇒ x = 15

∴ Side of P = x = 15 cm

Answer 2

Answer:

Given:-

• Ratio of area of square = 4 : 25
• side of s square = 6cm

Find:-

• length of side p?

Solution:-

Let us take the ratios of areas of s : p as 4x : 25x

From, question one side of s square = 6

we know that area of square = side²

$: { \sf{ \implies{ {6}^{2} = 4x }}} \\ \\: { \sf{ \implies{36 = 4x}}} \\ \\ : { \sf{ \implies{x = \frac{36}{4} }}} \\ \\ : { \sf{ \implies{x = 9}}}$

So, the value of x is 9

By Substituting x value in ratio,

$: { \sf{ \implies{4x:25x}}} \\ \\ : { \sf{ \implies{4(9):25(9)}}} \\ \\ : { \sf{ \implies{36:225}}}$

So, the area of p square is 225

$: { \sf{ \implies{ {p}^{2} = 225 }}} \\ \\ : { \sf{ \implies{p = \sqrt{225} }}} \\ \\ : { \sf{ \implies{p = 15}}}$

Therefore,

• length of side of p square is 15cm