Question

There are two squares and the ratio of their perimeters is 8:19. If the area of the first square is 1600 square meters then what is the area of the second square

Answer 1

answer in attachment

Answer 2

Answer:

The area of the second square is 9025 square meters

Step-by-step explanation:

Let the side of first square is x and side of the second square is y

Then, we have

$\frac{4x}{4y}=\frac{8}{19}\\\\y=\frac{19}{8}x......(1)$

Now, the area of the first square is 1600 square meters. It means we have

x^2=1600

x=40

Plugging this value in equation (1), we get

$y=\frac{19}{8}\cdot40\\\\y=95$

Therefore, the area of second square is given by

$A = y^2\\A=95^2\\A=9025m^2$

Thus, area of the second square is 9025 square meters