Question

There are two squares, and the ratios of their perimeters are 6:17 .If the area of the first square is 144 m2, then find the area of the second square?

Answer 1

Formula:

$\dfrac{\text{Area 1}}{\text {Area 2}} =\bigg( \dfrac{\text{Length 1}}{\text {Length 2}} \bigg)^2$

Find the area of the second square:

$\dfrac{\text{144}}{\text {Area}} =\bigg( \dfrac{\text{6}}{\text {17}} \bigg)^2$

$\dfrac{\text{144}}{\text {Area}} = \dfrac{\text{36}}{\text {289}}$

$36 \text{Area} = 144 \times 289$

$36\text{Area} = 41616$

$\text{Area} = 41616 \div 36$

$\text{Area} = 1156 \text{ m}^2$

Answer: 1156 m²