There are two stones with masses 4kg and 10kg which are at rest . A stone having mass 10 kg moves towards the east with a velocity of 5m/s. Find the velocity of the stone with mass 4 kg with respect to the ground.
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Answer:
The velocity of the heavier block (10kg) = 14m/s.
The velocity of COM is given by:
m
1
+m
2
m
1
v
1
+m
2
v
2
=
10+4
10×14+4×0
=10m/s since spring force is an internal force.
Explanation:
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