Question

There are two taps operating together to fill the tank. One fill the empty tank in 10 hours and Second one can empty the full tank in 12 hours. When the second tap is put on after 2 hours of the starting of the first tap, what is the total time taken to fill the empty tank (in hours).​

Answer 1

Answer:

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Answer 2

Answer:

A tap can fill an empty tank in 12 hours and another tap can empty half the tank in 10 hours It both the taps are opened simultaneously, how long would it take for the empty tank to be filled to half its capacity?

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Let, the total volume of the tank be x litres.

In case of first tap,

in 12 hrs, it supplies x litres of water

So, in 1 hr it supplies x/12 litres of water

And, in case of 2nd tap,

in 10 hrs, it removes x/2 litres of water

In 1 hr, it removes x/20 litres of water

Therefore after 1 hr the ultimate amount of water remaining in the tank, when both the taps are on..

=X/12-X/20.

=x/30

Let the required number of hours be Y

Then (x/30)*Y=X

Y=30 hrs (ans)