Question

There are two temples, one on each bank of a river, just opposite to each other. One temple is 50m high. From the top of this temple, the angle of depression of the top and the foot of the other temple are 30o and 60orespectively. Find the width of the river and the height of the other temple.

Answer 1

Answer:

Let AB and CD be the two two temples and Bc be the width of the river.

Then ∠ ADE =30⁰ and ∠ ACB = 60⁰

Given A = 50m

∴ In Δ ABC

tan 60⁰ = AB/BC

√3 = 50/BC

BC = 50/√3

= 50√3/3

= 28.867m

and In Δ AED

tan 30⁰ = AE/ED

tan 30⁰ = AB - BE/BC

tan 30⁰ = AB - DC/BC

 1/√3 = 50 - DC /50/√3

50/3 = 50 - DC

DC = 50 - 50/3

= 150/3 - 50/3

= 100/3 m

= 33.33 m

Hence the width of the river is 28.867m and height of the other temple is 33.33m.

Step-by-step explanation:

Answer 2

Answer:

And is

Step-by-step explanation:

Width 40. Height60