There are two therapies B₁ and B₂ available for curing a patient suffering from a certain disease.The patient can choose any one of the two therapies. If he selects therapy B₁ the probability of his recovery from the disease is 7/8 and if he selects therapy B₂ the the probability of his recovery from the disease is 9/10 (i) what is the probability that the patient is cured from the disease? (ii) Given that the patient is cured, what is the probability that he has selected therapy B₂?
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Answer:
71/80
9/20
Step-by-step explanation:
Equal probability to choose therapy
the probability that the patient is cured from the disease
= (1/2)(7/8) + (1/2)(9/10)
= 7/16 + 9/20
= 35/80 + 36/80
= 71/80
Patient cured when selected B₂ = 9/10
probability that he has selected therapy B₂ = 1/2
Probability = (9/10)/(1/2) = 9/20
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