There are two types of animals in a room some are cat and some are dogs each cat takes 7 biscuits and each dog takes 9 biscuits 355 biscuits are eaten by 45 animals find the number of cays and dogs
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cats=25
dogs=20
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dogs=20
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Answer:
Hence, Number of cats = 25 and number of dogs = 20
Step-by-step explanation:
Let the numbers of cats be x and number of dogs be y
Number of animals = 45
⇒ x + y = 45
⇒ x = 45 - y ......(1)
Also, each cat take 7 biscuits and each dog take 9 biscuits and total of 355 biscuits are taken
⇒ 7x + 9y = 355
Putting value of x from equation (1)
⇒ 7 (45 - y) + 9y = 355
⇒ 315 - 7y + 9y = 355
⇒ 2y = 40
⇒ y = 20
Also, x = 45 - y
⇒ x = 45 - 20
⇒ x = 25
Hence, Number of cats = 25 and number of dogs = 20
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