There are two urns. the first urn contains 3 red and 5 white balls whereas the second urn contains 4 red and 6 white balls. a ball is taken at random from the first urn and its transfer to second urn.now another is selected at random from the second urn.the probability of that the second ball would be?pls give explained answer
Answers
probability of that the second ball would be Red = 35/88 & white = 53/88
Step-by-step explanation:
the first urn contains 3 red and 5 white balls => total = 8 Balls
second urn contains 4 red and 6 white balls. => Total = 10 Balls
There can be two cases : Ball taken from UrnA is Red or White
Case 1 : Red is Taken from UrnA
Probability of Red = (3/8)
then second urn contains 5 Red & 6 White => total = 11
Probability of Red from UrnB = (3/8) (5/11) = 15/88
Probability of White from UrnB = (3/8) (6/11) = 18/88
Case 1 : White is Taken from UrnA
Probability of White = (5/8)
then second urn contains 4 Red & 7 White => total = 11
Probability of Red from UrnB = (5/8) (4/11) = 20/88
Probability of White from UrnB = (5/8) (7/11) = 35/88
probability of that the second ball would be Red = 15/88 + 20/88 = 35/88
probability of that the second ball would be White = 18/88 + 35/88 = 53/88
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Answer:
35/88
Step-by-step explanation:
click on above photo
