Question

there are two values of time for which a projectile is a the same height sum of these two times is equal to

Answer 1

Answer:

2u/g

Explanation:

suppose

a projectile is thrown up with initial velocity u

then

height h = ut - gt²/2 let g = 10m/s²

h = ut -5t²

5t² - ut + h = 0

t ={u ± √u² - 20h}/10

the sum of the two times = 2u/10 =2u/g = u/5