There are two varieties of tea worth Rs.90 per
kg and Rs.70 per kg. If X kg of 1st kind is
mixed with 56 kg of 2nd kind to get a profit
25% by selling the mixture at Rs.95 per kg
then X equals to:
Answers
Step-by-step explanation:
x kg of 90 and 56 kg of 70 is mixed then the average price
= x×90 + 56×70 /(x+56) = cp
sp = 95, profit = 25%,
profit = sp-cp/cp ×100
25 = 95 - cp/ cp ×100
0.25×cp = 95- cp
cp(1+.25) =95
cp = 95/1.25 = 76
apply alligation
90 70
76
76-70 90-76
=6 = 14
6:14 = 3:7
90rs is 3x kgs
70rs is 7x kgs
but 7x = 56
x = 56/7 =8
3x = 3×8 =24
weight of 90rs worth tea in the mixture = 24
Answer:
X = 24
Step-by-step explanation:
Recall the formula
Profit % =
Profit = Selling Price - Cost Price
Solution:
Cost of the first variety of tea = Rs.90
Cost of the second variety of tea = Rs. 70
Cost of Xkg of the first variety of tea = 90X
Cost of 56Kg of the second variety of tea = 56×70 = 3920
Total cost of Xkg of first variety and 56kg of second variety = 90X+3920
Total weight of the tea = X+56
Cost per kg =
So we have,
Cost Price = CP = -----------(1)
Selling Price = SP = 95
Profit % = 25%
Profit = SP - SP = 95 -CP
Profit % = ×100
25 = ×100
25CP = (95-CP)×100
25CP = 9500-100CP
125CP = 9500
CP =
CP =76 --------------(2)
Comparing Equations(1) and (2) we get
= 76
90X +3920 = 76(X+56)
90X +3920 = 76X+4256
90X - 76X = 4256 -3920
14X = 336
X = 24
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