There are two vessels containing the mixture of milk and water. In the first vessel the water is 2/3 of the milk and in the second vessel water is just 40% of the milk. In what ratio these are required to mix to make 24 litres mixture in which the ratio of water is to milk is 1 : 2 ?
Answers
Answer:
Ratios are 4:3 (4+3=7) and 2:3 (2+3=5). So LCM of 7, 5 is 35.
Now, for 35 liter mix.
Let M=milk,W=water
Vessel A,
M:W= 4:3 (4+3=7) means in 35 liter mix. Milk is 4*35/7=20 liter and water is 3×35/7=15 liter.
Vessel B,
M:W=2:3(2+3=5) means in 35 liter mix. Milk is 2×35/5=14 liter and water is 3×35/5=21 liter.
For Vessel C,
M:W=1:1(required)
Let ratio of Vessel A=x and Vessel B=y.
In Vessel C , both milk and water will be in equal quantity. So,
Net quantity of milk= Net quantity of water
20x+14y=15x+21y
5x=7y
x/y=7/5
So, x:y=7 :5
Vessel A : Vessel B:: 7:5
Step-by-step explanation:
please do follow me
Answer:
We will do this question using Alligation:
Water concentrations: 2/7[{=2/5(40%) of milk}V2] 2/5 (V1)
Required water concentration: 1/3
The ratio of V2 AND V1, i.e.., V2:V1: 1/15 (2/5-1/3) 1/21 (1/3-2/7)
= > 21:15 = 7:5
V2:V1 = 7:5
Answer; V1:V2 = 5:7
Answer: 5:7
Step-by-step explanation: