Question

There are two vessels which are filled with milk of two quantities worth rs.10 per litre and rs. 11 per litre .in what approximate ratio these two be mixed to get a new quality of milk of worth rs.10.6 litre?

Answer 1

let x litres of ₹10 milk and y litres if ₹11 milk
then
10x + 11y = 10.6(x+y)
0.4y = 0.6 x
x/y = 4/6 =2/3

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Answer 2

Answer:

Required Ratio of milks is 2 : 3

Step-by-step explanation:

Given:

Cost of the milk per liter of quantity 1 = Rs. 10

Cost of the milk per liter of quantity 2 = Rs. 11

To find: Ratio of milk of both quantities so that cost of mixture per liter is Rs. 10.6

let x be the Quantity of the milk 1 and y be the Quantity of the milk 2.

According to the question,

10x + 11y = 10.6( x + y )

10x + 11y = 10.6x + 10.6y

11y - 10.6y = 10.6x - 10x

0.4y = 0.6x

y/x = 0.6/0.4

y/x = 3/2

x/y = 2/3

Therefore, Required Ratio of milks is 2 : 3