Math, asked by contestcollections, 10 months ago

There are two vessels ,which is filled with milk and water in the ratio 5:3 and 2:3 respectively.In which proportions these mixture must be added so that the final mixture contain half milk and half water?

Answers

Answered by kittttu
1

Answer:

hopefully it will help u... please if possible mark my ans as brainliest...

Attachments:

contestcollections: Brother,solve my another question with the help of algebra- In what ratio must a person mix three kinds of metal costing Rs 60/kg,Rs 75/kg and Rs 100/kg so that the resultant alloy when sold at Rs 96/kg result in a gain of 20%?
SudevSKC20: 1:4:2 is the answer .this might be help you
contestcollections: solve it.
Answered by SudevSKC20
0

Answer:

7:5

Step-by-step explanation:

ratios 4:3(4+3=7) and 2:3(2+3=5).

it's LCM=35

now for 35 litre mix

vessel A,

M:W=(4+3=7) means 35litre mix.Milk is 4*35/7=20litre and water is 3*35/7=15litre

Vessel B,

M:W=2:3(2+3=5)means is35litre mix.Milk is2*35/5=14litre and water is 3*35/5=21litre

For Vessel C,

M:W=1:1(required)

let ratio of vessel A=X and Vessel B=y

In vessel C,both milk and water will be in equal quantity .so,

Net quantity of milk=Net quantity of water

20x+14y=15x+21y

5x=7y

x/y=7:5

So,x:y=7:5


contestcollections: Brother,the answer should be 4:5.
kittttu: brother i have answered it
contestcollections: Yup,u have answered but Sudev's answer is not correct.would u solve by his way?
kittttu: sorry bro..i cant be able to solve
contestcollections: No problemo!
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