There are two vessels ,which is filled with milk and water in the ratio 5:3 and 2:3 respectively.In which proportions these mixture must be added so that the final mixture contain half milk and half water?
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Brother,solve my another question with the help of algebra- In what ratio must a person mix three kinds of metal costing Rs 60/kg,Rs 75/kg and Rs 100/kg so that the resultant alloy when sold at Rs 96/kg result in a gain of 20%?
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7:5
Step-by-step explanation:
ratios 4:3(4+3=7) and 2:3(2+3=5).
it's LCM=35
now for 35 litre mix
vessel A,
M:W=(4+3=7) means 35litre mix.Milk is 4*35/7=20litre and water is 3*35/7=15litre
Vessel B,
M:W=2:3(2+3=5)means is35litre mix.Milk is2*35/5=14litre and water is 3*35/5=21litre
For Vessel C,
M:W=1:1(required)
let ratio of vessel A=X and Vessel B=y
In vessel C,both milk and water will be in equal quantity .so,
Net quantity of milk=Net quantity of water
20x+14y=15x+21y
5x=7y
x/y=7:5
So,x:y=7:5
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