there are two ways to solve this question. the faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). when you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
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Answer:
Heya Here's the required Answer mate
Question
- The equation 24x2+25x−47ax−2=−8x−3−53ax−2 is true for all values of x≠2a, where a is a constant.
- What is the value of a?
- A) -16
- B) -3
- C) 3
- D) 16
Solution
- There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:
- 24x2+25x−47=(−8x−3)(ax−2)−53
- You should then multiply (−8x−3) and (ax−2) using FOIL.
- 24x2+25x−47=−8ax2−3ax+16x+6−53
- Then, reduce on the right side of the equation
- 24x2+25x−47=−8ax2−3ax+16x−47
- Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
Hope it helps dear
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Answer:
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Step-by-step explanation:
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