there are two wires of the same length and of the same material and radii r and 2r. the ration of their specific resistance is
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R = (rho) * length/ area
R1 = rho * l / pi * r^2
R2 = rho * l / pi * 4r^2
Rho and length will be same for both the wires as it’s given in the question that both are of same length and same material.
R1/R2 = 4/1 (happens when all the other terms get cancelled out)
R1 = rho * l / pi * r^2
R2 = rho * l / pi * 4r^2
Rho and length will be same for both the wires as it’s given in the question that both are of same length and same material.
R1/R2 = 4/1 (happens when all the other terms get cancelled out)
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