Math, asked by tanmaykumarnayak, 1 year ago

there are35 chocolates. You have to divide them among three. The first one will get 1/2 of the total chocolates. The second will get 1/3rd and the third one will get 1/9th.can you divide the chocolates among the three without breaking the chocolates according to the plan?

Answers

Answered by BornLoser07
16
let's see it the other way you have 36 chocolates ,now it's quite easy to do.
first will get 18 chocolates
second will get 12 chocolates
third will get 4 chocolates
Answered by sushmaa1912
7

Given:

Total number of chocolates = 35

They have to be divided among three people.

Number of chocolates first person gets = \frac{1}{2} of total chocolates

Number of chocolates second person gets = \frac{1}{3} of total chocolates

Number of chocolates third person gets = \frac{1}{9} of total chocolates

To find:

Whether or not the chocolates be divided among three individuals without breaking the chocolate into pieces.

Solution:

Number of chocolates first person gets =\dfrac{1}{2} \ of \ 35

                                                                  =\dfrac{1}{2} \times 35 = 17.5

It is clear from the first person's share that the chocolate cannot be divided such that no chocolate gets broken down into pieces.

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