There exist a ΔABC with sides BC = 2 cm; AB = 4 cm and AC = 2 cm.
Answers
Answer:
Δ
ABC, BC=2cm, AB=4cm and AC = 2cm
This
Δ
ABC is not possible to construct because the condition is sum of lengths of two sides of a triangle should be greater than the third side.
AB<BC+AC
⇒
4<2+2
⇒
4=4,
Answer:
Verified by Toppr
Steps:
1. draw base AB=4cm
2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.
3. let C be the point of intersection of the above 2 lines.
4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.
5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1
6. join A3B and draw a parallel line B
′
A2
7. draw a line parallel to BC to intersect AC at C
′
Thus AB
′
C
′
is a required triangle.
Justification;
By construction,
AB
AB
′
=
AA3
AA2
=
3
2
also B
′
C
′
∥BC
∴∠AB
′
C
′
=∠ABC
In △AB
′
C
′
,△ABC
∠A=∠A
∠AB
′
C
′
=∠ABC
△AB
′
C
′
∼△ABC
⇒
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
∴
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
=
3
2