there exist a tower near Shankar's house . The top of the toweer AB is tied with steel wire and on ground it is tied with string support . One day tried to measure the longest wire AC using pythagoras theorem In figure th
e length is ( BC-60) . Please see the whole question in the image attached .
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Given : BC = 60 , AB = 80
Area of ΔABC
To Find : AC
Solution:
Applying Pythagoras theorem
AC² = AB² + BC²
=> AC² = 60² + 80²
=> AC² = 3600 + 6400
=> AC² = 10000
=> AC² = 100²
=> AC = 100 ft
Area of ΔABC = (1/2) AB * BC
= (1/2) 60 (80)
= 2400 sq ft
PC = √20² + 15² = 25 ft
length of hypotenuse in ΔABC = 100 ft
Area of Δ POC = (1/2) * 20 * 15
= 150 sq ft
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Answer:
i) In the figure,the length of wire AC is : (take BC= A 60ft)
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