Question

There exist two arithmetic series such that their sums are in the ratio 7n+1/4n+27. What will be the difference of the ratio of their eleventh terms(in simplified form)?

Answer 1

Answer

Is in the image given

Answer 2

Answer:

1

Step-by-step explanation:

Sum (n terms) = n/2 * [2a + (n-1)d]

S/S' = 7n+1/4n+27

7n+1/4n+27 = 2a+(n−1)d/2a'+(n−1)d'

{T}^11/{T'}base11 = 2a+(n−1)d/2a'+(n−1)d'

for n = 21 we get

148/111=2a+20d/2a'+20d'

4/3=a+10d/a'+10d'

4/3=1.333 ----> approximately it can be written as 1.

Source: gfg