Question

There exists a claim that if allowed to run for 100.0 years, two
cesium clocks, free from any disturbance, may differ by only about
0.020 s. Using that discrepancy, find the uncertainty in a cesium
clock measuring a time interval of 1.0 s.​

Answer 1

$\huge\bf{Explanation:-}$

100 years = 100 × 365 × 24 × 3600 s

error in 109 years is ∆t = 0.02 s

$\implies$error in 1s duration = ∆t\t

$= \frac{0.02}{100 \times 365 \times 24 \times 3600} \\ = 6 \times 10 ^{ - 12} s \: of \: the \: order \: of \: 10 ^{ - 11} to \: 10 ^{ - 12}$