Math, asked by hazimsaud2001, 1 day ago

There is 1L of 96% acid in a pot. 1/4 L of that acid is taken out and replaced by water. Again, 1/6 L of acid is take out and replaced by water. What is the final percentage of the acid?​

Answers

Answered by somumounika1657
0

Answer:

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Answered by reachanif
2

Answer:

4%

Step-by-step explanation:

Amount of acid initially = 96/100 * 1000

                                       = 960 ml

First, 1/4 acid is taken out,

So now amount of acid = 1/4 * 960

                                       = 240 ml

Then, 1/6 of acid is taken out,

So now amount of acid = 1/6 * 240

                                       = 40 ml

So, 40 ml is acid and the rest is water.

Therefore, the percentage of the acid is 4%.

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