Question

There is 22 friends (A1, A2, A3....A22).If A1 have to have shake with all without repeat.
How many handshakes possible?

Answer 1

Answer:

Step-by-step explanation:

Total number of friends = 22

So,

No. of possible handshakes is given by

$\sf{{\,}^{22}{C}_{2}}$

$\sf{=\dfrac{(22)!}{(2)!(20)!}}$

$\sf{=\dfrac{22\times21\times(20)!}{(2)!(20)!}}$

$\sf{=\dfrac{22\times21}{2\times1}}$

$\sf{=11\times21}$

$\sf{=231}$