Math, asked by surjitkhalsa7890, 10 months ago

there is 60 ltr milk in a vessel.10 ltr.milk is takan out and replaced with water.this process is repeated one more time.now 60 ltr.milk is put in the vessel and 10 ltr.mixture is taken out.now find the ratio off milk and water in the vessel.

Answers

Answered by shishank70
0

Answer:

approximately 8:1 is the correct answer.

Step-by-step explanation:

Ratio of Milk : Water, before again adding 60ltr. milk is

= (60 -10)/ (10 ) = 50/10 = 5 : 1.

Now, After repeating the process.

Milk : water = (50 +50)/(10 + 10) = 100/20=

5:1.

Now, after adding 60 ltr. of milk the ratio becomes,

Milk : Water = (100+60)/20 = 160/20 =8:1.

Now, If we take 10 ltr. of mixture out of the vessel we will be taking out,

(8 × 10)/(8 + 1) = 80/9 = 8.89 ltr of Milk and,

(1× 10)/(8+1) = 10/9 = 1.11 ltr. of water.

So,

Final ratio becomes = (160 - 8.89)/(20 - 1.11)= 141.11/ 18.89 = 7.9947062 : 1

or approximately 8:1.

I hope it helps u.

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