Question

There is 7.6% increase in total volume, when 23.9 mL CHCl3 (d = 1.5 g cm2) is mixed with 115.5 mL. CCl4 (d=1.6 g cm 3). What is the molarity of CHCl3 in the resulting solution, in mol L ¹?​

Answer 1

Answer:

Concept :

A chemical equation is a symbolic representation of a chemical reaction in the form of symbols and formulae, where the reactant entities are given on the left and the product entities are given on the right, with a plus sign separating the entities in both the reactants and the products and an arrow pointing in the direction of the products to indicate the reaction's direction. The absolute values of the stoichiometric numbers are shown as coefficients next to the symbols and formulas of the entities. Jean Beguin drew the first chemical equation in 1615.

Explanation:

• For solution 1,

              Mass of Chcl3 = density × volume

                                       = 1.5×23.9

                                       = 35.85g.

               Now molar of ChCl3 = 119.5

             •°• moles of ChCl3 in solutions = 35.85/119.5

                                                                 = 0.3 moles.

• For solution 2,

                Mass of ChCl3 = 11.5×1.6

                                         = 184.8 g

               •°• Moles = 1.55 moles.

              •°• Total moles = 1.55+0.3

                                      = 1.85 moles

Now, total volume of the mixture,

= 23.9 + 115.5 + 7.6/100× (23.9+115.5)

=  139.4+10.3944

= 149.9944 ml

•°• Molarity = 1.85/149.8944×10^-3

                  = 12.333M

                  = 12 mol $L^{-1}$.

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