Math, asked by pv6101996, 4 months ago

there is 80% acid and the rest is water in a mixture. find out how many mixture is drawn out and replace with same quantity of water to make the acid and water ratio to 4:3​

Answers

Answered by SwastikPrasad678
0

Answer:

2/7th

Step-by-step explanation:

Let the total quantity of mixture be 70 litres.

Therefore, Quantity of acid= 70*80/100= 56 litres

After replacement the quantity of acid

= 70*4= 40 litres

7

Therefore, [56-40]= 16 litres of acid is removed from the origin mixture.

Let x litres of the mixture is removed and replacement by water

= x*80/100= 16

= x= 20 litres

Therefore, Required part of the mixture= 20/70= 2/7

Similar questions