There is 80% increase in an amount in 8 years at simple interest. what will be the compound interest of rs. 14,000 after 3 years at the same rate
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9
Let P be Rs.100
Simple Interest = Rs. 80 ( ∵ 80% increase due to the simple interest)
Rate of interest=(100×SI) / PT
=100×80100×8
=10% per annum
compound interest of Rs. 14,000 after 3 years at 10%
P = Rs.14000
T = 3 yrs
R = 10%
Amount after 3 years
=P(1+R100)^t
=14000(1+10100)^3
=14000(110100)^3
=14000(1110)^3
=14×113
=18634
Compound Interest = Rs.18634 - Rs.14000 = Rs.4634 [answer]
P.s Get Online Math help from best Online Tutor @ https://tutstu.com/tutors/Math/sub/18/HIGH-SCHOOL
Simple Interest = Rs. 80 ( ∵ 80% increase due to the simple interest)
Rate of interest=(100×SI) / PT
=100×80100×8
=10% per annum
compound interest of Rs. 14,000 after 3 years at 10%
P = Rs.14000
T = 3 yrs
R = 10%
Amount after 3 years
=P(1+R100)^t
=14000(1+10100)^3
=14000(110100)^3
=14000(1110)^3
=14×113
=18634
Compound Interest = Rs.18634 - Rs.14000 = Rs.4634 [answer]
P.s Get Online Math help from best Online Tutor @ https://tutstu.com/tutors/Math/sub/18/HIGH-SCHOOL
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2
4634 rs as compound interest
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