Question

There is a 3 x 3 x 3 cube which consists of twenty seven 1 x 1 x 1 cubes. It is tunneled
removing cubes from the coloured squares. Find:
(1) Fraction of number of small cubes removed to the number of small cubes left ing
cube.
(ii) Fraction of the number of small cubes removed to the total number of small cubes
(iii) What part is (ii)

Answer 1

Answer:

Step-by-step explanation:

Given  There is a 3 x 3 x 3 cube which consists of twenty seven 1 x 1 x 1 cubes. It is tunneled  by removing cubes from the coloured squares. Find:

(1) Fraction of number of small cubes removed to the number of small cubes left in given  cube.

(ii) Fraction of the number of small cubes removed to the total number of small cubes

(iii) What part is (ii) of (i)

1   Now the number of small cubes that is removed will be 1+ 1+1+1+1+1+1 = 7

    We get the required fraction as 7/20 (because 27 – 7 = 20)

2.  Next the required fraction will be 7/27

3.  So part will be 7/27 / 7/20 = 7/27 x 20/7 = 20/27

Answer 2

Answer:Given  There is a 3 x 3 x 3 cube which consists of twenty seven 1 x 1 x 1 cubes. It is tunneled  by removing cubes from the coloured squares. Find:

(1) Fraction of number of small cubes removed to the number of small cubes left in given  cube.

(ii) Fraction of the number of small cubes removed to the total number of small cubes

(iii) What part is (ii) of (i)

1   Now the number of small cubes that is removed will be 1+ 1+1+1+1+1+1 = 7

   We get the required fraction as 7/20 (because 27 – 7 = 20)

2.  Next the required fraction will be 7/27

3.  So part will be 7/27 / 7/20 = 7/27 x 20/7 = 20/27