there is a 90 degree bend in a pipeline in which water is flowing at Speed v. The cross sectional area of the pipe is A. The force exerted by the pipe walls on water at the band is
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this can be solved by using the concept of fluid mechanics. you can imagine it as when the water flows through the pipe it pushes the pipe forward and after bending it pushes it backwards. so the resultant force is the answer. F = √2×roh × A × V^2
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